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- : ; When a▓ït▓/h▓ = ╜ last term vanishes, giving:
- : ; ⌡ 1 └
- : ; u(t+1) = ╜ ■ 1 0 1 ■u - u(t-1)
- : ; ┴ 1 π
- : ;
- : ; This needs only 4 ADD/SUB and one SAR operation per mesh point!
-
- Tough shit!
-
- I never thought of that. Hmm. So you don't keep a speed array at all! That should
- speed up my routine considerably. I did my stuff in machine language this
- weekend and was already stunned by the result... But, it was over 40 instructions
- per mesh point
-
- Thanx for posting this.
- --
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- A DVision Software Group division
- ====== Simm (germans@cs.vu.nl) - Coder / Musician / Graphician / etc. ======
- "Whatever you do, continue to F5" - Space Manbow / Konami
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